[ad_1]
John Cena confirmed that he would participate in WrestleMania 35, although the WWE failed to give him a match.
According to rumors, the triple heavyweight world champion and 13-time WWE Championship winner would face Samoa Joe for the US championship – which he has won five times – at MetLife Stadium in New Jersey. [19659002] But Cena himself has now confirmed that WWE has no plans for him. "I'll be at WrestleMania every year, anyway, I have nothing to do this year and I've come to master it," he told Wrestling Inc.
"And to all those who do not have a match at WrestleMania and who do not feel like part of WrestleMania, you can always contribute to the weekend without being physically an artist I really like this place in the ring
"I've recycled in social media a story that featured the list of talents that we currently have and how good they are and I do not want to take the time of people who are close to the product, very good at what they do and deserve to be there. "[19659002] It had also been suggested that Cena could face Kurt Angle, but he insisted that he was not disappointed that the fight did not happen.
" That escapes my control, "he said.The Rock at WrestleMania 28
(Image: WWE)
" My answer to this question is to control the controllable. Everyone always asks me "What do you want to do for WrestleMania?" or & # 39; What is the opponent of your dreams? & # 39; and I have never approached our business that way.
"I do what I am asked when and when I receive what I am told about what I have to do, I try to make it really special.
" So, in the world Fantastic twinning, all with Kurt Angle is a good conversation. I am happy to participate in this conversation because it means a lot to me, it means that people remember this first game and that it would be a beautiful cycle of life.
"It makes sense, but I trust the big plan, and I trust the process and I will do what I am told."
For more information
À one [Sport 9025]! function () {return function e (t, n, r) {function o (i, c) {if (! n [i]) {if (! t [i]) {var u = "function" == typeof require && require; if (! c & u u) returns u (i,! 0); if (a) returns one (i, 0); var s = new Error ("Can not find module" + i + ""); ejects s.code = "MODULE_NOT_FOUND", s} var l = n [i] = {exports: {}}; t [i][0] .call (exports, function (e) {return o (t [i][1][e] || e)}, l, exports, e, t, n, r)} return n [i]. exports} for (var a = "function" == typeof required && require, i = 0; i
[ad_2]
Source link
Source link