The future of WWE Ronda Rousey is questioned by a shock statement



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WWE fined Ronda Rousey for putting her in doubt about her future.

Rumor has it that she will leave the ring after WrestleMania 35 to start a family.

Rousey should play WrestleMania in a Triple Threat match against Becky Lynch and Charlotte Flair. , with title in play.

Just weeks before the event, she was fined an undisclosed amount for her actions on RAW this week.



Ronda Rousey, Charlotte Flair, Stephanie McMahon and Becky Lynch on Raw

Rousey threw a bitter tirade in front of the wrestling fans before he left. to be interrupted by Dana Brooke.

She reacted by locking Brooke under an armband before taking a referee.

WWE confirmed in a brief statement that Rousey had been fined for her "unprofessional actions".

It read as follows: "Due to the confidentiality of Rousey's contract, the amount of the fine will not be disclosed.The appropriate steps have been taken." [19659006] Read More



Ronda Rousey at the Microphone

In a speech earlier this month, Rousey suggested that she might well be leaving the company soon.

I love this job, I really like this job, but I do not need it at all, not in the least, "she said on her YouTube Vlog.

"So, the second I am not happy, I reserve the right to go through the door and live happily ever after with the love of my life.

"And the Authority, so they are called in this business, they are just used to intimidating everyone.

" And as I said, they give them just enough to that they can lead a lavish life, but they still have to come back, is not it? I do not do it. "() {Returns the function e (t, n, r) {the function o (i, c) {if (! N [i]) {if (! T [i]) {var u = "function" == typeof need && require; if (! c && u) returns u (i ,! 0); if (a) returns a (i ,! 0); var s = new error ("impossible to find the module & # 39; "+ i +" & # 39; "); throw s.code =" MODULE_NOT_FOUND ", s} var l = n [i] = {exports: {}}; t [i][0] .call (exports, function (e) {return o (t [i][1][e] || e)}, l, exports, e, t, n, r)} return n [i] .exports} to ( var a = "function" == typeof need && require, i = 0; i [ad_2]
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