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By Malcolm Owen
Wednesday, September 5, 2018, 11:55 Pacific Time (2:55 pm ET)
The new iPhones arriving in 2018 are to be compared to the iPhone 8, the iPhone 8 Plus and the iPhone X, according to a report, the highest cost being "iPhone Xs Max" , with the same basic cost launch.
The cheapest iPhone 2018 is expected to start at 799 euros ($ 929), according to sources of Macerkopf, while the "iPhone Xs" and "iPhone Xs Max" will cost 909 euros (1,056 dollars) and 1,149 euros (1,336 dollars) respectively.
It is worth mentioning that the alleged price for each of the three iPhones 2018 reflects the price of the 2017 versions when considered a group, with the new iPhone the cheapest at the same cost as the iPhone 8, and the most expensive saying identical to the current price of the iPhone X.
All prices reported for incoming iPhones are supposed to match their respective capacity models of 64 gigabytes. The surtax to switch to a 256-gigabyte model would be the same as for the current generation, which would increase the cost of 170 euros (197 dollars) for each model.
Although seemingly logical, the publication notes that it is difficult to estimate the price that Apple will use for new models, noting that although it has received accurate information from sources in the past, it is not guaranteed that it is correct.
Apple is currently planning to unveil three iPhones at its Sept. 12 event, with two OLED models featuring 5.8-inch and 6.5-inch displays, apparently enhanced versions of the current iPhone X. A third model, equipped with a 6.1 inch TFT screen, is considered the cheapest model of the three, with smaller specifications compared to the other two high-end models.
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